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Product identities

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  • Sebastian Martin
    Sebastian Martin escribió: Dear colleagues: I have found two identities: 1) Product[k^Floor[n/k],{k,1,n}]=
    Message 1 of 4 , Jan 17, 2007
      Sebastian Martin <sebi_sebi@...> escribió:

      Dear colleagues:

      I have found two identities:

      1) Product[k^Floor[n/k],{k,1,n}]=
      Product[Floor[n/k]!,{k,1,n}]


      2)(Product[(i^j)*(j^i),{i,1,n},{j,1,n}]/Product[i!*j!,{i,1,n},{j,1,n}])^(1/n)=
      Product[C(n,i),{i,0,n}]

      OEIS A001142

      This identities are known?

      Sincerely

      Sebastian Martin Ruiz






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