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Re: [PrimeNumbers] number length

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  • Phil Carmody
    ... ? 2*1660693*log(2)/log(10) 999836.8131784078460461793726 ... My answer s very accurate, It appears that you ve mixed 1660693 and 1660963. Phil () ASCII
    Message 1 of 5 , Jan 4, 2007
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      --- leavemsg1 <leavemsg1@...> wrote:
      > Hello, Group.
      >
      > Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?
      >

      ? 2*1660693*log(2)/log(10)
      999836.8131784078460461793726

      > I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
      > and arrived at L(N)= 999,999. How inaccurate is it?

      My answer's very accurate,
      It appears that you've mixed 1660693 and 1660963.

      Phil

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    • Phil Carmody
      ... Maybe it does, maybe it doesn t, but it s the wrong tool for the job. Calculating the value of a simple expression you re only going to find the size of is
      Message 2 of 5 , Jan 4, 2007
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        --- Jacques Tramu <jacques.tramu@...> wrote:
        > >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?
        >
        > >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
        > >and arrived at L(N)= 999,999. How inaccurate is it?
        >
        > GMP gives : 998838

        Maybe it does, maybe it doesn't, but it's the wrong tool for the job.

        Calculating the value of a simple expression you're only going to find the size
        of is lazy thinking.

        The size of a^b is b times the size of a.
        The size of a*b is the sum of the sizes of a and b.

        Phil

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      • pbtoau
        I get about 6.5*10^999836. This would indicate a length of 999837 digits. - David ... +1? ... suggested ... job. ... find the size
        Message 3 of 5 , Jan 6, 2007
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          I get about 6.5*10^999836. This would indicate a length of 999837
          digits.

          - David
          --- In primenumbers@yahoogroups.com, Phil Carmody <thefatphil@...>
          wrote:
          >
          > --- Jacques Tramu <jacques.tramu@...> wrote:
          > > >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)
          +1?
          > >
          > > >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone
          suggested
          > > >and arrived at L(N)= 999,999. How inaccurate is it?
          > >
          > > GMP gives : 998838
          >
          > Maybe it does, maybe it doesn't, but it's the wrong tool for the
          job.
          >
          > Calculating the value of a simple expression you're only going to
          find the size
          > of is lazy thinking.
          >
          > The size of a^b is b times the size of a.
          > The size of a*b is the sum of the sizes of a and b.
          >
          > Phil
          >
          > () ASCII ribbon campaign () Hopeless ribbon campaign
          > /\ against HTML mail /\ against gratuitous bloodshed
          >
          > [stolen with permission from Daniel B. Cristofani]
          >
          > __________________________________________________
          > Do You Yahoo!?
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          > http://mail.yahoo.com
          >
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