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Re: [PrimeNumbers] number length

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  • Phil Carmody
    ... ? 2*1660693*log(2)/log(10) 999836.8131784078460461793726 ... My answer s very accurate, It appears that you ve mixed 1660693 and 1660963. Phil () ASCII
    Message 1 of 5 , Jan 4, 2007
      --- leavemsg1 <leavemsg1@...> wrote:
      > Hello, Group.
      >
      > Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?
      >

      ? 2*1660693*log(2)/log(10)
      999836.8131784078460461793726

      > I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
      > and arrived at L(N)= 999,999. How inaccurate is it?

      My answer's very accurate,
      It appears that you've mixed 1660693 and 1660963.

      Phil

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    • Jacques Tramu
      ... GMP gives : 998838 [Non-text portions of this message have been removed]
      Message 2 of 5 , Jan 4, 2007
        >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?

        >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
        >and arrived at L(N)= 999,999. How inaccurate is it?

        GMP gives : 998838

        [Non-text portions of this message have been removed]
      • Phil Carmody
        ... Maybe it does, maybe it doesn t, but it s the wrong tool for the job. Calculating the value of a simple expression you re only going to find the size of is
        Message 3 of 5 , Jan 4, 2007
          --- Jacques Tramu <jacques.tramu@...> wrote:
          > >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?
          >
          > >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
          > >and arrived at L(N)= 999,999. How inaccurate is it?
          >
          > GMP gives : 998838

          Maybe it does, maybe it doesn't, but it's the wrong tool for the job.

          Calculating the value of a simple expression you're only going to find the size
          of is lazy thinking.

          The size of a^b is b times the size of a.
          The size of a*b is the sum of the sizes of a and b.

          Phil

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        • pbtoau
          I get about 6.5*10^999836. This would indicate a length of 999837 digits. - David ... +1? ... suggested ... job. ... find the size
          Message 4 of 5 , Jan 6, 2007
            I get about 6.5*10^999836. This would indicate a length of 999837
            digits.

            - David
            --- In primenumbers@yahoogroups.com, Phil Carmody <thefatphil@...>
            wrote:
            >
            > --- Jacques Tramu <jacques.tramu@...> wrote:
            > > >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)
            +1?
            > >
            > > >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone
            suggested
            > > >and arrived at L(N)= 999,999. How inaccurate is it?
            > >
            > > GMP gives : 998838
            >
            > Maybe it does, maybe it doesn't, but it's the wrong tool for the
            job.
            >
            > Calculating the value of a simple expression you're only going to
            find the size
            > of is lazy thinking.
            >
            > The size of a^b is b times the size of a.
            > The size of a*b is the sum of the sizes of a and b.
            >
            > Phil
            >
            > () ASCII ribbon campaign () Hopeless ribbon campaign
            > /\ against HTML mail /\ against gratuitous bloodshed
            >
            > [stolen with permission from Daniel B. Cristofani]
            >
            > __________________________________________________
            > Do You Yahoo!?
            > Tired of spam? Yahoo! Mail has the best spam protection around
            > http://mail.yahoo.com
            >
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