number length

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• Hello, Group. Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1? I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested and
Message 1 of 5 , Jan 4, 2007
Hello, Group.

Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?

I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
and arrived at L(N)= 999,999. How inaccurate is it?

Thanks, Bill.
• ... ? 2*1660693*log(2)/log(10) 999836.8131784078460461793726 ... My answer s very accurate, It appears that you ve mixed 1660693 and 1660963. Phil () ASCII
Message 2 of 5 , Jan 4, 2007
--- leavemsg1 <leavemsg1@...> wrote:
> Hello, Group.
>
> Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?
>

? 2*1660693*log(2)/log(10)
999836.8131784078460461793726

> I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
> and arrived at L(N)= 999,999. How inaccurate is it?

It appears that you've mixed 1660693 and 1660963.

Phil

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• ... GMP gives : 998838 [Non-text portions of this message have been removed]
Message 3 of 5 , Jan 4, 2007
>Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?

>I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
>and arrived at L(N)= 999,999. How inaccurate is it?

GMP gives : 998838

[Non-text portions of this message have been removed]
• ... Maybe it does, maybe it doesn t, but it s the wrong tool for the job. Calculating the value of a simple expression you re only going to find the size of is
Message 4 of 5 , Jan 4, 2007
--- Jacques Tramu <jacques.tramu@...> wrote:
> >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?
>
> >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
> >and arrived at L(N)= 999,999. How inaccurate is it?
>
> GMP gives : 998838

Maybe it does, maybe it doesn't, but it's the wrong tool for the job.

Calculating the value of a simple expression you're only going to find the size
of is lazy thinking.

The size of a^b is b times the size of a.
The size of a*b is the sum of the sizes of a and b.

Phil

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• I get about 6.5*10^999836. This would indicate a length of 999837 digits. - David ... +1? ... suggested ... job. ... find the size
Message 5 of 5 , Jan 6, 2007
I get about 6.5*10^999836. This would indicate a length of 999837
digits.

- David
--- In primenumbers@yahoogroups.com, Phil Carmody <thefatphil@...>
wrote:
>
> --- Jacques Tramu <jacques.tramu@...> wrote:
> > >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)
+1?
> >
> > >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone
suggested
> > >and arrived at L(N)= 999,999. How inaccurate is it?
> >
> > GMP gives : 998838
>
> Maybe it does, maybe it doesn't, but it's the wrong tool for the
job.
>
> Calculating the value of a simple expression you're only going to
find the size
> of is lazy thinking.
>
> The size of a^b is b times the size of a.
> The size of a*b is the sum of the sizes of a and b.
>
> Phil
>
> () ASCII ribbon campaign () Hopeless ribbon campaign
> /\ against HTML mail /\ against gratuitous bloodshed
>
> [stolen with permission from Daniel B. Cristofani]
>
> __________________________________________________
> Do You Yahoo!?
> Tired of spam? Yahoo! Mail has the best spam protection around
> http://mail.yahoo.com
>
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