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number length

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  • leavemsg1
    Hello, Group. Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1? I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested and
    Message 1 of 5 , Jan 4, 2007
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      Hello, Group.

      Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?

      I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
      and arrived at L(N)= 999,999. How inaccurate is it?

      Thanks, Bill.
    • Phil Carmody
      ... ? 2*1660693*log(2)/log(10) 999836.8131784078460461793726 ... My answer s very accurate, It appears that you ve mixed 1660693 and 1660963. Phil () ASCII
      Message 2 of 5 , Jan 4, 2007
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        --- leavemsg1 <leavemsg1@...> wrote:
        > Hello, Group.
        >
        > Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?
        >

        ? 2*1660693*log(2)/log(10)
        999836.8131784078460461793726

        > I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
        > and arrived at L(N)= 999,999. How inaccurate is it?

        My answer's very accurate,
        It appears that you've mixed 1660693 and 1660963.

        Phil

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      • Jacques Tramu
        ... GMP gives : 998838 [Non-text portions of this message have been removed]
        Message 3 of 5 , Jan 4, 2007
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          >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?

          >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
          >and arrived at L(N)= 999,999. How inaccurate is it?

          GMP gives : 998838

          [Non-text portions of this message have been removed]
        • Phil Carmody
          ... Maybe it does, maybe it doesn t, but it s the wrong tool for the job. Calculating the value of a simple expression you re only going to find the size of is
          Message 4 of 5 , Jan 4, 2007
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            --- Jacques Tramu <jacques.tramu@...> wrote:
            > >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?
            >
            > >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
            > >and arrived at L(N)= 999,999. How inaccurate is it?
            >
            > GMP gives : 998838

            Maybe it does, maybe it doesn't, but it's the wrong tool for the job.

            Calculating the value of a simple expression you're only going to find the size
            of is lazy thinking.

            The size of a^b is b times the size of a.
            The size of a*b is the sum of the sizes of a and b.

            Phil

            () ASCII ribbon campaign () Hopeless ribbon campaign
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          • pbtoau
            I get about 6.5*10^999836. This would indicate a length of 999837 digits. - David ... +1? ... suggested ... job. ... find the size
            Message 5 of 5 , Jan 6, 2007
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              I get about 6.5*10^999836. This would indicate a length of 999837
              digits.

              - David
              --- In primenumbers@yahoogroups.com, Phil Carmody <thefatphil@...>
              wrote:
              >
              > --- Jacques Tramu <jacques.tramu@...> wrote:
              > > >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)
              +1?
              > >
              > > >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone
              suggested
              > > >and arrived at L(N)= 999,999. How inaccurate is it?
              > >
              > > GMP gives : 998838
              >
              > Maybe it does, maybe it doesn't, but it's the wrong tool for the
              job.
              >
              > Calculating the value of a simple expression you're only going to
              find the size
              > of is lazy thinking.
              >
              > The size of a^b is b times the size of a.
              > The size of a*b is the sum of the sizes of a and b.
              >
              > Phil
              >
              > () ASCII ribbon campaign () Hopeless ribbon campaign
              > /\ against HTML mail /\ against gratuitous bloodshed
              >
              > [stolen with permission from Daniel B. Cristofani]
              >
              > __________________________________________________
              > Do You Yahoo!?
              > Tired of spam? Yahoo! Mail has the best spam protection around
              > http://mail.yahoo.com
              >
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