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Re: Cubic x^3 + x^2 + x + t prime generators

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  • Robert
    ... Oops, how did I get this muddled? Too many beers when I wrote the response most probably. I meant to say: k^p-(k-1)^p, where p is prime Regards Robert
    Message 1 of 8 , Apr 1, 2006
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      --- In primenumbers@yahoogroups.com, "Mark Underwood"
      <mark.underwood@...> wrote:
      >

      >
      > Robert, k^n-k^(n-1) has of course factors of k so I assume you did a
      > typo somewhere?
      >
      > Mark
      >

      Oops, how did I get this muddled? Too many beers when I wrote the
      response most probably. I meant to say:

      k^p-(k-1)^p, where p is prime

      Regards

      Robert Smith
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