Re: Cubic x^3 + x^2 + x + t prime generators
- --- In email@example.com, "Mark Underwood"
>Oops, how did I get this muddled? Too many beers when I wrote the
> Robert, k^n-k^(n-1) has of course factors of k so I assume you did a
> typo somewhere?
response most probably. I meant to say:
k^p-(k-1)^p, where p is prime