To my sincere opinion it is not necessary, and certainly not called for, to

use the name of God in the sense displayed in a couple of previous messages.

Although probably used here with good intent. Let's just stick to math.

Jan van Delden

----- Original Message -----

From: <primenumbers@yahoogroups.com>

To: <primenumbers@yahoogroups.com>

Sent: Wednesday, February 08, 2006 11:16 AM

Subject: [PrimeNumbers] Digest Number 1834

There are 5 messages in this issue.

Topics in this digest:

1. second mail and two problems of me......

From: ali palang <x_3_14159265@...>

2. YOU KNOW ITS PROOF

From: "THANOOP T" <thanoopt@...>

3. Re: YOU KNOW ITS PROOF

From: mikeoakes2@...

4. New CC Record

From: Gary Chaffey <garychaffey2@...>

5. Re: YOU KNOW ITS PROOF

From: Cletus Emmanuel <cemmanu@...>

________________________________________________________________________

________________________________________________________________________

Message: 1

Date: Tue, 7 Feb 2006 01:10:34 -0800 (PST)

From: ali palang <x_3_14159265@...>

Subject: second mail and two problems of me......

in the name of god

hello to all

these two problems have planned by me,2 years ago;

try to solve them;but there are too easy,just for amusement:

1.suppose this a,b are from N,and a,b>1,prove that,if a+b=p,and p is prime

number

then,(a,b)=1.

...........................

2.find number of pairs (a,b),so a,b>1,,(a,b)=1 and a+b=p,that p is prime

number.

~~~~~~~~~~~~~~~~

and then

under the protection of god.

---------------------------------

Yahoo! Mail - Helps protect you from nasty viruses.

[Non-text portions of this message have been removed]

________________________________________________________________________

________________________________________________________________________

Message: 2

Date: Tue, 07 Feb 2006 11:43:40 -0000

From: "THANOOP T" <thanoopt@...>

Subject: YOU KNOW ITS PROOF

let A anb B are vectorspaces over C such that

A= { z:exp(az) is algebraic)}

B= { z:exp(bz) is algebraic)}

such that a/b not in Q (rationals)

then how to show that

dim(A intersection B) <=1 or <=2

if any one know the proof pls sent

************************************ Thanoop T

TIFR BANGALORE

________________________________________________________________________

________________________________________________________________________

Message: 3

Date: Tue, 07 Feb 2006 07:13:33 -0500

From: mikeoakes2@...

Subject: Re: YOU KNOW ITS PROOF

In an email dated Tue, 7 2 2006 11:43:40 am GMT, "THANOOP T"

<thanoopt@...> writes:

> let A anb B are vectorspaces over C such that

> A= { z:exp(az) is algebraic)}

> B= { z:exp(bz) is algebraic)}

> such that a/b not in Q (rationals)

>then how to show that

> dim(A intersection B) <=1 or <=2

> if any one know the proof pls sent

I have 2 comments.

(a) This is not a well-posed question, for example:

"A= { z:exp(az) is algebraic)}" is not a meaningful definition of a vector

space over the complex numbers, and so on.

(b) Your question has nothing to do with prime numbers, and so should not

have been posted to this newsgroup.

-Mike Oakes

________________________________________________________________________

________________________________________________________________________

Message: 4

Date: Tue, 7 Feb 2006 21:19:01 +0000 (GMT)

From: Gary Chaffey <garychaffey2@...>

Subject: New CC Record

I have just found the following record Cunningham Chain (1st Kind) length 5

:-

(2^n)*5864262128*1201#-1 For n=0..4

The smallest member of this chain has 514 digits and as far as I know is a

new record for a length 5 CC (1st Kind).....Although it does fall 99 digits

short of the record length 5 CC (2nd Kind)!

Regards

Gary

---------------------------------

Win a BlackBerry device from O2 with Yahoo!. Enter now.

[Non-text portions of this message have been removed]

________________________________________________________________________

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Message: 5

Date: Tue, 7 Feb 2006 13:31:02 -0800 (PST)

From: Cletus Emmanuel <cemmanu@...>

Subject: Re: YOU KNOW ITS PROOF

...And finally, we don't do other people's homework for them ...

mikeoakes2@... wrote: In an email dated Tue, 7 2 2006 11:43:40 am GMT,

"THANOOP T" <thanoopt@...> writes:

> let A anb B are vectorspaces over C such that

> A= { z:exp(az) is algebraic)}

> B= { z:exp(bz) is algebraic)}

> such that a/b not in Q (rationals)

>then how to show that

> dim(A intersection B) <=1 or <=2

> if any one know the proof pls sent

I have 2 comments.

(a) This is not a well-posed question, for example:

"A= { z:exp(az) is algebraic)}" is not a meaningful definition of a vector

space over the complex numbers, and so on.

(b) Your question has nothing to do with prime numbers, and so should not

have been posted to this newsgroup.

-Mike Oakes

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