## Re: [PrimeNumbers] YOU KNOW ITS PROOF

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• ... I have 2 comments. (a) This is not a well-posed question, for example: A= { z:exp(az) is algebraic)} is not a meaningful definition of a vector space
Message 1 of 3 , Feb 7, 2006
In an email dated Tue, 7 2 2006 11:43:40 am GMT, "THANOOP T" <thanoopt@...> writes:

> let A anb B are vectorspaces over C  such that
>       A= { z:exp(az) is algebraic)}
>       B= { z:exp(bz) is algebraic)}
>        such that a/b  not in Q (rationals)
>then how to show that
>  dim(A intersection B) <=1 or <=2
>  if any one know the proof pls sent

(a) This is not a well-posed question, for example:
"A= { z:exp(az) is algebraic)}" is not a meaningful definition of a vector space over the complex numbers, and so on.

(b) Your question has nothing to do with prime numbers, and so should not have been posted to this newsgroup.

-Mike Oakes
• ...And finally, we don t do other people s homework for them ... ... I have 2 comments. (a) This is not a well-posed question, for example: A= { z:exp(az) is
Message 2 of 3 , Feb 7, 2006
...And finally, we don't do other people's homework for them ...

mikeoakes2@... wrote: In an email dated Tue, 7 2 2006 11:43:40 am GMT, "THANOOP T" <thanoopt@...> writes:

> let A anb B are vectorspaces over C such that
> A= { z:exp(az) is algebraic)}
> B= { z:exp(bz) is algebraic)}
> such that a/b not in Q (rationals)
>then how to show that
> dim(A intersection B) <=1 or <=2
> if any one know the proof pls sent

(a) This is not a well-posed question, for example:
"A= { z:exp(az) is algebraic)}" is not a meaningful definition of a vector space over the complex numbers, and so on.

(b) Your question has nothing to do with prime numbers, and so should not have been posted to this newsgroup.

-Mike Oakes

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