Re: Real Count-Down Prime
Andrey Kulsha wrote:
> The seriesSorry, there was a typo: k goes from 2 to infinity.
Phil Carmody wrote:
> OK, that does seem to make sense. Thanks.It converges for any n>1.
> (Am I right in thinking that the sum of 1/(k.log(k)^n)
> would diverge for any constant n?)
You may calculate an integral(f(k)*dk,C,+infinity) to check
if f(k) is smooth for C<=k<+infinity.