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What are the other factors and number which:

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  • John W. Nicholson
    do the following (note the plus/minus and what it equals also notice the 137 and 173 between the two groups): factor ((23#)^3 +/- 1) = 2^12 * 3 * 5^12 * 137 *
    Message 1 of 1 , Apr 1, 2005
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      do the following (note the plus/minus and what it equals also notice
      the 137 and 173 between the two groups):

      factor ((23#)^3 +/- 1) = 2^12 * 3 * 5^12 * 137 * 27015639337
      factor ((23#)^3 +/- 2) = 2^12 * 3 * 5^12 * 137 * 27015639337
      factor ((23#)^3 +/- 4) = 2^12 * 3 * 5^12 * 137 * 27015639337
      factor ((23#)^3 +/- 8) = 2^12 * 3 * 5^12 * 137 * 27015639337
      factor ((23#)^3 +/-16) = 2^12 * 3 * 5^12 * 137 * 27015639337


      factor ((24!)^3 +/- 1) = 2^59 * 5^58 * 173^2 * 972260323

      Is this a odd perfect square?
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