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Re: [PrimeNumbers] Known conjeture

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  • Jud McCranie
    ... No, this is easy. If the two numbers weren t 6n+/-1 then one of the numbers would be 6n+3. But if it is 6n+3 then it is divisible by 3. So if n=0 then
    Message 1 of 3 , Jul 1, 2001
      At 12:15 AM 7/2/2001 +0000, jmvolpe@... wrote:
      >Hello:
      >Mi name is Juan Volpe and I like prime numbers too.
      >I´ve studied prime numers and I foud that every pair of primes only
      >2 apart are like 6n +-1 e.g. (5,7), (11,13), (17,19).
      >It's this one unsolved problem to?

      No, this is easy. If the two numbers weren't 6n+/-1 then one of the
      numbers would be 6n+3. But if it is 6n+3 then it is divisible by 3. So if
      n=0 then you have the prime 3 (and the pair 3,5), but for n>1 6n+3 has 3 as
      a factor, so isn't prime.


      +--------------------------------------------------------+
      | Jud McCranie |
      | |
      | 137*2^261147+1 is prime! (78,616 digits, 5/2/00) |
      +--------------------------------------------------------+
    • Murad AlDamen
      Hi Juan Please See Http://www.primepuzzles.net the prime boxes and www.angelfire.com/de2/abbas/prime1.html Sincerely AlDamen, Murad ... Your online tourguide
      Message 2 of 3 , Jul 3, 2001
        Hi Juan
        Please See Http://www.primepuzzles.net the prime boxes
        and
        www.angelfire.com/de2/abbas/prime1.html
        Sincerely
        AlDamen, Murad

        --- jmvolpe@...
        > wrote:
        >Hello:
        >Mi name is Juan Volpe and I like prime numbers too.
        >I=B4ve studied prime numers and I foud that every pair of primes only=20
        >2 apart are like 6n +-1 e.g. (5,7), (11,13), (17,19).
        >It's this one unsolved problem to?
        >I will apreciate yor answer.
        >Bye
        >
        >
        >Unsubscribe by an email to: primenumbers-unsubscribe@egroups.com
        >The Prime Pages : http://www.primepages.org
        >
        >=20
        >
        >Your use of Yahoo! Groups is subject to http://docs.yahoo.com/info/terms/=
        >=20

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