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Re: primes of the form (n!/2)^2+/-1

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  • richard042@yahoo.com
    Subtracting 1 from any square 4 would also be fruitless, of course. -Dick
    Message 1 of 3 , Feb 14, 2005
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      Subtracting 1 from any square>4 would also be fruitless, of course.

      -Dick


      --- In primenumbers@yahoogroups.com, mikeoakes2@a... wrote:
      >
      > In a message dated 14/02/2005 00:58:34 GMT Standard Time,
      > reddwarf2956@y... writes:
      >
      > Is there a search for these forms?
      >
      > (n!/2)^2(+/-)1
      > (n#/2)^2(+/-)1
      >
      >
      >
      > John
      >
      > I've not seen any search results reported for the first form.
      > Go for it!
      >
      > Searching on the second would be fruitless.
      > (n#/2) is odd, so these forms are always divisible by 2.
      >
      > -Mike Oakes
      >
      >
      > [Non-text portions of this message have been removed]
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