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Re: [PrimeNumbers] Re: large composite number....

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  • Yves GALLOT
    ... I tried to write a simple expression with no where and I wrote an incorrect one :o( 641 divides all the GFN of the form (2^a*5^b)^2^5+1, where a is odd
    Message 1 of 4 , Jun 28, 2001
      > Yves Gallot wrote:
      >
      >> 641 = 5*2^7+1 divides F_5 and GF(5, 5) then it
      >> divides all the GFN of the form (2^(2a)*5^b)^2^5+1.
      >
      > Not if b is even.
      >
      > (2^c*5^d)^32=(-1)^(c+d) mod 641
      > for all non-negative integers c,d.

      I tried to write a simple expression with no "where" and
      I wrote an incorrect one :o(

      641 divides all the GFN of the form (2^a*5^b)^2^5+1,
      where a is odd and b is even, or a is even and b is odd.

      Yves
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