Thanks for your reply, I've read about the Chinese Remainder Theorem

but I've struggled with understanding its implications.

I'm also interested in functions which produce as their output the

positive integers or lists of integers whose composition (with

multiplicity) follows that of the positive integers. In this case,

finding difference between successive pairs of prime/integer which

satisfy the requirements and the starting term produces the sequence

3, 6, 9, 12, etc. (which reduces to 1, 2, 3, 4, etc.) and Omega(n) of

the resulting sequence is equal to Omega(n) + 1 of the positive

integers. If anyone happens to know where I can find more info about

functions with these properties, I'd appreciate a pointer in the

right direction (books, links, etc). Thanks!

-Andrew-

--- In

primenumbers@yahoogroups.com, "Jens Kruse Andersen"

<jens.k.a@g...> wrote:

> asposer wrote:

> > Desired n: 3

> >

> > 5 * 12 = 60

> > 7 * 9 = 63

> > 11 * 6 = 66

> > 3 * 23 = 69

>

> This is always possible for any n and any order of the primes.

> The problem is just solving a set of modular equations.

> Your example, with x for the first product, is the smallest

solution to:

> x = 0 (mod 5)

> x = -3 (mod 7)

> x = -6 (mod 11)

> x = -9 (mod 3)

> CRT (Chinese Remainder Theorem) says it can always be solved when

the numbers

> are relatively prime, and primes are that.

>

> Setting up such a system of modular equations with carefully chosen

residues

> (not k*n) is a great way to find large prime gaps, by ensuring many

numbers with

> a small factor.

>

> > is it possible to do this with

> > an infinitely large list of primes?

>

> No. A solution must have given finite values for x and n. The

average prime gap

> tends to infinite, so infinitely many of the primes will be larger

than the

> number they would have to divide.

>

> --

> Jens Kruse Andersen