>

http://listserv.nodak.edu/scripts/wa.exe?A2=ind0012&L=nmbrthry&P=R529&D=0&H=0&O=T&T=1

I looked at your link and it is quite interesting. I have a couple of

comments though. You mention that G0(n) = n*(1+i)^n + 1 and is

related to Cullens but later state that G0(n) = n*2^(n/2) + 1 and then

go on to show primes of that form. Am I missing something? n*(1+i)^n

+ 1 =/= n*2^(n/2) + 1. The same could be said of G2(n) and Woodalls.

You also have Ne(n) as n^2*2^n + 1, which pre-dates the Hyper-Cullen

search of Steven Harvey. He has noted your finds as he searches up to

200000.

--Mark- In a message dated 26/02/04 14:20:52 GMT Standard Time, mgrogue@...

writes:

> You mention that G0(n) = n*(1+i)^n + 1 and is

It is if n = 0 mod 8, which was (one of) the values I was talking about.

> related to Cullens but later state that G0(n) = n*2^(n/2) + 1 and then

> go on to show primes of that form. Am I missing something? n*(1+i)^n

> + 1 =/= n*2^(n/2) + 1.

>

Remember: (1+i)^2 = 2*i.

-Mike Oakes

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