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RE: [PrimeNumbers] N-th prime boundary?

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  • Paul Leyland
    I believe that N/(ln N - 2) will serve your purpose. Paul
    Message 1 of 2 , Dec 23, 2003
      I believe that N/(ln N - 2) will serve your purpose.


      Paul


      > -----Original Message-----
      > From: William Bouris [mailto:melangebillyb@...]
      > Sent: 23 December 2003 16:16
      > To: primenumbers@yahoogroups.com
      > Subject: [PrimeNumbers] N-th prime boundary?
      >
      > Hello, Group.
      >
      > Is there a simple formula for calculating an upper boundary
      > which would always contain a particular nth-prime number?
      > ie. input n --> formula ---> calculated limit > prime p. I
      > bet that this question has been asked several times, but I
      > just need a "slightly larger than p" value for any given n.
      >
      > Thanks in advance, Bill
      >
      >
      >
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