if A and B are events in & and P(B)>=0 then the conditional

probability

of A given B(written) P(A/B)= P(ANB)/P(B)

N=intersect sign

P('/F) is a probability,conditional probabilities satisfy the

kolmogorov's 1)-2)-3) axioms

1) 0<=P('/F)<=1

2) P(&/F)=1

3) if Ei....... ,i=1,2,3.....

are mutually exclusive events then

infinite infinite

p(U Ei/F) = E P(Ei/F)

i=1 i=1

U=union set

E=Sigma(additional set)

how would you prove 3rd{(3)} then??

toyanc yazgan

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