## Re: Brialliant numbers

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• Uh, consecutive? The only way I can think of to define two brilliant numbers as consecutive is if they were next to each other in a list of PRP s or
Message 1 of 4 , Jun 2, 2003
Uh, consecutive?

The only way I can think of to define two brilliant numbers as
consecutive is if they were next to each other in a list of PRP's or
pseudoprimes.

(Or perhaps I am just another trolling victim?
...excuse me, I need to remove this hook before it gets set too
firmly... ;-)

Bruce

--- In primenumbers@yahoogroups.com, "Jon Perry" <perry@g...> wrote:
> from;
>
> http://www.alpertron.com.ar/BRILLIANT.HTM
>
> Is anyone searching for the longest run of consecutive brilliant's?
>
> Jon Perry
• Based on the URL mentioned (http://www.alpertron.com.ar/BRILLIANT.HTM), there is a section which states: 1000=10*100=20*50=25*40 1001=11*91=13*77 1002=...
Message 2 of 4 , Jun 3, 2003
Based on the URL mentioned (http://www.alpertron.com.ar/BRILLIANT.HTM),
there is a section which states:

1000=10*100=20*50=25*40
1001=11*91=13*77
1002=...
1003=17*59
1004=...
1005=15*67
1006=...
1007=19*53
1008=12*84=14*72=16*63=18*56=21*48=24*42=28*36
1009=...
1010=101*10
1011=...
1012=11*92=22*46=23*44
1013=...
1014=13*78=26*39
1015=39*35
1016=...

and so 1001-1007 are 'consecutive' and all brilliant. Except for this is
confusing as 15 really equals 3*5. Is this sort of data really necessary?

Continuing, it seems 1003 and 1007 are 2-brilliant, and thus can we define
'consecutive' from this? Note that if 1009 was 3-brilliant, then this would
be OK.

Jon Perry
perry@...
http://www.users.globalnet.co.uk/~perry/maths/
BrainBench MVP for HTML and JavaScript
http://www.brainbench.com
• Think about divisibilty by three. Please. Regions [x,x+k] where the density of brilliant numbers is larger than normal. Jon Perry perry@globalnet.co.uk
Message 3 of 4 , Jun 3, 2003