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Re: [PrimeNumbers] strong symmetry of number of factors

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  • Dick Boland
    Hello, Given any two consecutive sequences of an equal number of consecutive integers, heuristically, the ratio of the number of primes in each sequence
    Message 1 of 2 , Jun 1, 2001
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      Hello,
      Given any two consecutive sequences of an equal number
      of consecutive integers, heuristically, the ratio of the
      number of primes in each sequence approaches unity.
      So it's not surprising, in fact, it's what you'd expect.
      -Dick

      --- Bill Krys <billkrys@...> wrote:
      > Dick,
      >
      > The latter,
      >
      > Bill
      >
      > --- Dick Boland <richard042@...> wrote:
      > > Hi Bill,
      > >
      > > Maybe, are you talking about the segment
      > > as one side of the symmetry (symmetrical about 2^n),
      > > or both sides of the symmetry within the segment
      > > (symmetrical about 3*2^(n-1))?
      > >
      > > -Dick Boland
      > >
      > > --- Bill Krys <billkrys@...> wrote:
      > > > Hello,
      > > >
      > > > Has anyone noticed the strong degree of symmetry
      > > for
      > > > the number of prime factors on a segment from 2^n
      > > to
      > > > 2^(n+1)?
      > > >
      > > > Bill
      > > >
      > > > =====
      > > > Bill Krys
      > > > Email: billkrys@...
      > > > Toronto, Canada (currently: Beijing, China)
      > > >
      > > > __________________________________________________
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      >
      > =====
      > Bill Krys
      > Email: billkrys@...
      > Toronto, Canada (currently: Beijing, China)
      >
      > __________________________________________________
      > Do You Yahoo!?
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