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FLT 'attempt'

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  • Jon Perry
    Let x^n+y^n=z^n Then (x+y)^n-z^n = x^n+y^n-z^n + [] = [] where [] is the innards of (x+y)^n However every term in [] contains at least an xy component. x+y=Z
    Message 1 of 1 , Mar 31, 2003
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      Let x^n+y^n=z^n

      Then (x+y)^n-z^n = x^n+y^n-z^n + [] = []

      where [] is the 'innards' of (x+y)^n

      However every term in [] contains at least an xy component.

      x+y=Z is greater than z, and [] doesn't change regardless of how we assign x
      and y.

      So let x=z, and we have a contradiction:

      (x+y)^n-z^n will not be divisible by z unless y=kz, k>0.

      Jon Perry
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