Re: [PrimeNumbers] Factor Record
> Yes, I see it now,I'm not sure that you can clearly define "irreducible in the logical
> (p + 1)^p == p + 1 mod p
> (p^p + 1)^p == p^p + 1 mod p etc
> So we have a strange object, an open `closed' form. The closure
> here being only in the logical order, and semi-open in the algebraic
> order (extended via the theorem). I did say the theory starts.
> Of course you can only use 1 theorem once in any form, no repeated
> applications etc. Forms must be irreducible in the logical as well
> as algebraic order. Once again the point of this is that we can
order". Or what you mean by using 1 theorem only once. After all,
I'm sure that most of the methods we use actually use certain
theorems meny times over: Example
Theorem: for any integers x and y, x*y = y*x.
Does that mean they are discounted?
To my mind, every theorem is reducible in a logical sense, except
of course, the axioms of the logical system...
Yours, Mike H...
> now produce ever larger numbers of which we know the factor.Michael Hartley : Michael.Hartley@...
> There is an error in my previous posting, q = 3*p + 1 is difficult
> for q and p odd prime. If q = k*p +m in a Generalised Sophie
> Germain then k and m have opposite parity
> Paul Mills
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