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7811Factor patterns

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  • djbroadhurst
    Jul 1, 2002
      Likewise, if a*b=-1 mod 24 then a+b=0 mod 24
      with residue pairs {1,23},{5,19},{7,17},{11,13}
      since n^2=1 mod 24 for all n with gcd(n,24)=1

      It obviously fails mod 48:
      5*19 = -1 mod 48
      5+19 != 0 mod 48
      and mod 120:
      7*137 = -1 mod 120
      7+137 != 0 mod 120
      (yes, I know I could have used {7,17},
      but 137 took my fancy:-)

      David
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