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23049Re: A PRP of the form 2*k*p +1

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  • Alan R Powell
    Sep 1, 2011
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      --- In primenumbers@yahoogroups.com, "Peter Lesala" <plesala@...> wrote:
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      > Keen to find prime factors of 2^333019 - 1, I went on to test 2*k*p + 1 for k = 10^100000. The test gives
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      > 2*(10^100000 + 50617) + 1 as a probable prime of 100006 digits; using Primeform.
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      > Peter.
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      > [Non-text portions of this message have been removed]
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      > [Non-text portions of this message have been removed]
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      Peter

      Am I missing something, according to Mathematica:

      2*(10^100000+50617) + 1 ends in a 5

      2*(10^100000*50617) + 1 is divisible by 967 & 23473

      Regards

      Alan
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