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22707Re: stronger than BPSW?

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  • paulunderwooduk
    Apr 30, 2011
      --- In primenumbers@yahoogroups.com, "paulunderwooduk" <paulunderwood@...> wrote:
      >
      > Hi,
      >
      > Pari/GP implements Baillie-PSW with a strong 2-SPRP test and a strong -- where the jacobi symbol is -1 -- test on x^2-P*x-1 with minimal P.
      >
      > In my paper "quadratic composite tests", available in the files section of this group, I give another 3-selfridge test based on a strong a-SPRP test and a strong lucas test on x^2-a*x+1 with minimal a.
      >
      > In a way my test is stronger in that writing n+1 as 2^s*d, I can say
      >
      > V(a,1,<(n+1)/(2^r)-1,<(n+1)/(2^r)>) is either <a,2> for r=s; or is <-a,-2> for some r: 0<r<=s
      >
      > In matrix terms I am taking the successive square roots of
      >
      > [a,-1;1,0]^(n+1) == [1,0;0,1] (for a prime)
      >
      > Neat, eh?
      >

      I should have said the matrices are equivalent mod n.

      Another thing I have noticed for numbers +-2 (mod 5) is the following:

      [3,-1;0,1]^((n+1)/2) == [-1,0;0,-1] (mod n)
      [7,-1;0,1]^((n+1)/2) == [1,0;0,1] (mod n)

      where n is prime.

      Is this pattern of square roots -- one +I and one -I -- carried to all strong tests where the "a" differ by 4?

      Paul
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