--- In

primenumbers@yahoogroups.com, "David Broadhurst" <d.broadhurst@...> wrote:

>

> --- In primenumbers@yahoogroups.com,

> "Maximilian Hasler" <maximilian.hasler@> wrote:

>

> > [1 1 3 2 1 1 1 1 1]R=10, Q=3

>

> I think you are wrong, Maximilian.

>

> With Q = 3 and R = 10, I did not obtain 3 units from

> (x^n+y^n)/(x+y) with

> x = sqrt(R)/2 + sqrt(R-4*Q)/2

> y = sqrt(R)/2 - sqrt(R-4*Q)/2

> and integer n > 1.

>

> The only non-trivial case that I found was with

> Q = 2 and R = 7

> which I strongly presume to be Mike's discovery.

>

> But maybe I screwed up?

No - I screwed up!

Neglected the existence of nontrivial square roots (for even n...)

Maximilian,

strong supporter of the SSSR.