- May 7 8:20 PM--- In primenumbers@yahoogroups.com,

"Maximilian Hasler" <maximilian.hasler@...> wrote:

> [1 1 3 2 1 1 1 1 1]R=10, Q=3

I think you are wrong, Maximilian.

With Q = 3 and R = 10, I did not obtain 3 units from

(x^n+y^n)/(x+y) with

x = sqrt(R)/2 + sqrt(R-4*Q)/2

y = sqrt(R)/2 - sqrt(R-4*Q)/2

and integer n > 1.

The only non-trivial case that I found was with

Q = 2 and R = 7

which I strongly presume to be Mike's discovery.

But maybe I screwed up?

David - << Previous post in topic Next post in topic >>