19587Re: [PrimeNumbers] Re: Prize Puzzle : Primality Conjecture
- Sep 10, 2008Hi Adam,
>> If x > 3 and k > x , then A(x) will be prime if no valueAdam's proposed counterexample:
>> T(k) exists such that 1 < T(k) < B(x) is a square.
> When x=9, k=10, then A(9)=361 is not prime, T(10)=361 is a square,Umm... pardon me? How does this contradict Aldrich's conjecture? As far as
> 10=k > x=9, 9=x >3, T(k) = 361 is between 1 and B(x)=1681.
I understood the claim, A(x) is claimed to -be a prime- under the
assumption that -no- value of T(k) between 1 and B(x) is a square.
[Name] Peter Kosinar [Quote] 2B | ~2B = exp(i*PI) [ICQ] 134813278
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