19584Re: Prize Puzzle : Primality Conjecture
- Sep 10, 2008When x=9, k=10, then A(9)=361 is not prime, T(10)=361 is a square,
10=k > x=9, 9=x >3, T(k) = 361 is between 1 and B(x)=1681.
Please contact me off list for mailing address for my $50 prize.
There are 644 other counterexamples for x<=1000.
--- In firstname.lastname@example.org, "aldrich617" <aldrich617@...>
> I offer a $50 prize to the first person who can submit
> a verifiable counterexample or proof by 10/1/8
> for the following primality conjecture:
> x, A(x), B(x), k, T(k) : integers;
> Let A(x) = 5x^2 - 5x +1;
> Let B(x) = 25x^2 - 40x + 16;
> Let T(k) = 5*(2*k -1)^2 - 4*A(x) ;
> If x > 3 and k > x , then A(x) will be prime if no value
> T(k) exists such that 1 < T(k) < B(x) is a square.
> Aldrich Stevens
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