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  • leavemsg1
    Sep 30, 2007
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      I am not satisfied that Li(x) describes the number of primes < x

      I have a new calculation that gives...

      x= 1000 Ki(1000)= 167.9 and...
      x= 7919 Ki(7919)= 1000.756

      are they accurate?

      would someone suggest another slight larger x?

      so I can compute Ki(x)...

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