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18533Re: [PrimeNumbers] triangle, row sums = Sigma(n)

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  • Phil Carmody
    Jan 6, 2007
      --- matrixmonitor <matrixmonitor@...> wrote:
      > 1,2,1,3,0,1,4,2,0,1,5,0,0,0,1,6,3,2,0,0,1,7,0,0,0,0,0,1,8,4,0,2,0,0,0,
      > %T A126988
      > 1,9,0,3,0,0,0,0,0,1,10,5,0,0,2,0,0,0,0,1,11,0,0,0,0,0,0,0,0,0,1,12,6,4
      > ,
      > %U A126988 3,0,2,0,0,0,0,0,0
      > %N A126988 Triangle, row sums = Sigma(n).

      That much seems true.

      > %C A126988 Row sums = A000203, (Sigma(n)): 1, 3, 4, 7, 6, 12, 8,
      > 15,... Sigma(n) is the sum of the divisors of the integer n.
      > Conjecture: The sequence of parsed terms in Sigma(n) is the reversal

      What the blazes are 'parsed' terms?

      > of non-zero row terms in the triangle A126988.
      > %D A126988 David Wells, "Prime Numbers, the Most Mysterious Figures
      > in Math", John Wiley & Sons, Inc, 2005, Appendix B.
      > %F A126988 Row sums of a triangle in which k-th column (k=0,1,2...)
      > is (1,2,3,...) interspersed with n consecutive zeros, starting after
      > the "1".

      This sequence isn't the row sums of any triangle, it is a triangle.

      The descriptions are garbled, just as would be expected from:

      > %A A126988 Gary W. Adamson (qntmpkt(AT)yahoo.com), Dec 31 2006

      So, matrixmonitor, I don't remember seeing you post before. You're not just
      another sock-puppet for that previous known spewer of
      /stuff-of-questionable-quality/ are you?


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