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18529Re: [PrimeNumbers] number length

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  • Phil Carmody
    Jan 4, 2007
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      --- Jacques Tramu <jacques.tramu@...> wrote:
      > >Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?
      >
      > >I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
      > >and arrived at L(N)= 999,999. How inaccurate is it?
      >
      > GMP gives : 998838

      Maybe it does, maybe it doesn't, but it's the wrong tool for the job.

      Calculating the value of a simple expression you're only going to find the size
      of is lazy thinking.

      The size of a^b is b times the size of a.
      The size of a*b is the sum of the sizes of a and b.

      Phil

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