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18528Re: [PrimeNumbers] number length

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  • Phil Carmody
    Jan 4, 2007
      --- leavemsg1 <leavemsg1@...> wrote:
      > Hello, Group.
      >
      > Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?
      >

      ? 2*1660693*log(2)/log(10)
      999836.8131784078460461793726

      > I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
      > and arrived at L(N)= 999,999. How inaccurate is it?

      My answer's very accurate,
      It appears that you've mixed 1660693 and 1660963.

      Phil

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