18527Re: [PrimeNumbers] number length
- Jan 4, 2007
>Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?GMP gives : 998838
>I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
>and arrived at L(N)= 999,999. How inaccurate is it?
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