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18526number length

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  • leavemsg1
    Jan 4, 2007
      Hello, Group.

      Can someone calculate the length of N= (2^1660693)*(2^1660693+21)+1?

      I esimated it as [(2*1660693)*((log 2)/(log 10))] as someone suggested
      and arrived at L(N)= 999,999. How inaccurate is it?

      Thanks, Bill.
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