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18344RE: odd perfect form

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  • leavemsg1
    Sep 1, 2006
      Sorry,... the formula should have been posted as...

      (3^(2n-2))*(3^(2n-1)-1)/2.

      I thought about it while driving home last night.

      This idea follows from (2^(n-1))*(2^n-1) where 3 is subs. in for 2 and
      2n-1 in for n. Division by 2 in the formula correctly calculates the
      progressive sums for 1 + 3 + 9 + 27 + etc,...

      Thanks, Bill