- Nov 13, 2004Jack wrote:-
>>Can anybody find any longer such chains each with an equal number

I wrote:

>>of divisors, either with 4, 8, or some other number?

>With 3 divisors, each must be the square of a prime, of course.

In fact, there are chains of length 2, but no longer.

>Are there any such chains of length > 1? (I haven't searched.)

[

The first few are:-

2^2, 3^2

5^2, 7^2

29^2, 41^2

]

The proof is relatively straightforward.

Anyone?

-Mike Oakes

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