- Oct 31, 2003Hello,
Thanks for your response to the last question. For those of
you who cannot wait until Xmas here is another question. There may be
others as well.
Find the least 3 integer cubes so that X^3 = b, Y^3 = a + b and
Z^3 = 2a + b. I.e. 3 cubes in arithmetic progression. If that is
too hard , try 2 cubes in AP (!) or too easy, try 4 cubes in AP etc.
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