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  • paulmillscv
    Oct 31, 2003
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      Thanks for your response to the last question. For those of
      you who cannot wait until Xmas here is another question. There may be
      others as well.

      Find the least 3 integer cubes so that X^3 = b, Y^3 = a + b and
      Z^3 = 2a + b. I.e. 3 cubes in arithmetic progression. If that is
      too hard , try 2 cubes in AP (!) or too easy, try 4 cubes in AP etc.

      Paul Mills
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