- Oct 31, 2003Hello,

Thanks for your response to the last question. For those of

you who cannot wait until Xmas here is another question. There may be

others as well.

Find the least 3 integer cubes so that X^3 = b, Y^3 = a + b and

Z^3 = 2a + b. I.e. 3 cubes in arithmetic progression. If that is

too hard , try 2 cubes in AP (!) or too easy, try 4 cubes in AP etc.

Regards,

Paul Mills

Kenilworth,

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