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10632Re: Is phi(p^2-1)/(p^2-1) bounded?

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  • David Broadhurst <d.broadhurst@open.ac.u
    Jan 3, 2003
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      > Lower bound - anyone care for a stab?


      We believe (but cannot prove)
      that there are an infinite number of primes of
      the form primorial+1. That would be enough
      to make f(p)=phi(p^2-1)/(p^2-1)
      as close to zero as one likes.

      At present we know that
      p=392113#+1 is prime,
      giving (a la Mertens)
      f(p) < 0.0436

      Can anyone get lower than that?

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