10632Re: Is phi(p^2-1)/(p^2-1) bounded?
- Jan 3, 2003Phil:
> Lower bound - anyone care for a stab?0.
We believe (but cannot prove)
that there are an infinite number of primes of
the form primorial+1. That would be enough
to make f(p)=phi(p^2-1)/(p^2-1)
as close to zero as one likes.
At present we know that
p=392113#+1 is prime,
giving (a la Mertens)
f(p) < 0.0436
Can anyone get lower than that?
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