Loading ...
Sorry, an error occurred while loading the content.
 

Re: [primeform] Probable factorization of 3 consecutive 64868-digit integers

Expand Messages
  • Jens Kruse Andersen
    ... You mailed 18 minutes after the record was added. That was fast! The hit was prp64853 = (3045*2^215472-2)/(2*17*1151*27067*173473). Chris Chatfield found
    Message 1 of 5 , Sep 15, 2007
      David Broadhurst wrote:
      > "Jens Kruse Andersen" wrote:
      >
      >> There is obviously no plan to prove prp60203.
      >
      > But there was plan to improve on that probable factorization:
      >
      > http://hjem.get2net.dk/jka/math/consecutive_factorizations.htm
      >> n-1 = 3^2*11*13*22091*417293*c64854

      You mailed 18 minutes after the record was added. That was fast!
      The hit was prp64853 = (3045*2^215472-2)/(2*17*1151*27067*173473).
      Chris Chatfield found 3045*2^215472-1 in 2005:
      http://primes.utm.edu/primes/page.php?id=75494

      > Perhaps this trawl will run, and run, making Jens
      > update his own k=3 record at frequent intervals?

      It's still running. For how long is not decided, and there are
      probably only few hits left on known primes.
      I don't expect to search above the ongoing twin prime search at
      k*2^333333+/-1 - at least not before they actually find a twin and set
      a record. By then there will also be a Chen prime record to retake...

      --
      Jens Kruse Andersen
    Your message has been successfully submitted and would be delivered to recipients shortly.