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Re: [podcasters] can you subscribe someone else to an rss feed?

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  • Michael Sitarzewski
    Check out the options with http://feedburner.google.com - there s an email subscription option there. Michael. :) Sent from my iPad 2. ... [Non-text portions
    Message 1 of 3 , Mar 28, 2011
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      Check out the options with http://feedburner.google.com - there's an email subscription option there.

      Michael. :)

      Sent from my iPad 2.

      On Mar 28, 2011, at 12:16 AM, Gwen Orel <gwenorel@...> wrote:

      > I have an rss feed for my podcast (second episode went up today! and it's on itunes!) and though I was able to subscribe my mother on email she saw the rss feed and likes it.
      >
      > Is there a way I can do that for her? If there is I haven't figured it out.
      >
      > Thanks!
      >
      > (I know that ofcourse she can do it herself, but i have a reason for asking!)
      >
      >


      [Non-text portions of this message have been removed]
    • Shawn Thorpe
      If she s an iTunes user, you can create an iTunes protocol link like this: itpc://urlOfYourPodcastFeed Send that link to your mom via e-mail. When she clicks
      Message 2 of 3 , Mar 30, 2011
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        If she's an iTunes user, you can create an iTunes protocol link like this:
        itpc://urlOfYourPodcastFeed
        Send that link to your mom via e-mail. When she clicks the link, it'll spawn
        iTunes and automatically subscribe her to your podcast feed.

        On Sun, Mar 27, 2011 at 11:16 PM, Gwen Orel <gwenorel@...> wrote:

        >
        >
        > I have an rss feed for my podcast (second episode went up today! and it's
        > on itunes!) and though I was able to subscribe my mother on email she saw
        > the rss feed and likes it.
        >
        > Is there a way I can do that for her? If there is I haven't figured it out.
        >
        > Thanks!
        >
        > (I know that ofcourse she can do it herself, but i have a reason for
        > asking!)
        >
        >


        [Non-text portions of this message have been removed]
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