opening file whose name is stored in var
I have a file that changes name to the date and is stored in a
variable : $report= $date.pl.
I have file1.pl which opens another file2.pl using system('....') but
I need to pass this $report name to open the $date.pl file so file2.pl
can use it to append it's data to it.
ps= Charles you are the best!!!!