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Re: [PBML] How can i take one column of one string?

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  • Marcos Onisto
    Hello, One more question. I have the output below, I m taking the five field that is ..%, but I d to take the only value without the % character.
    Message 1 of 6 , Dec 14, 2006
      Hello,

      One more question. I have the output below, I'm taking the five field that is ..%, but I'd to take the only value without the % character.

      /dev/dsk/c0t0d0s0 491831 347447 95201 79% /
      /dev/dsk/c0t0d0s3 17144018 3403114 13569464 21% /usr
      /dev/dsk/c0t0d0s6 1370511 96072 1219619 8% /export/home

      Is there one easy way to do it?

      I really appreciate some help.

      Thanks a lot,

      Marcos


      Marcos Onisto <mlonisto@...> wrote: Hello,

      That's it! It's work but I'm trying to understand how It act.

      Thanks a lot,

      Marcos

      Robert Brown <rdabman4@...> wrote: One possible answer

      my ($strg,$pct)="";
      my @flds=();
      $strg="/dev/dsk/cotodos6 1370511 96072 1219619 8% /export/home";
      @flds=split(" ",$strg);
      $pct=$flds[4]; # arrays start from zero
      print "Fifth column field is $pct\n";

      ----- Original Message ----
      From: Marcos Onisto <mlonisto@...>
      To: perl-beginner@yahoogroups.com
      Sent: Monday, December 11, 2006 1:29:31 PM
      Subject: [PBML] How can i take one column of one string?

      Hello All,

      I have one string that follow below. How can i take the 8% or exactly 5 column?

      /dev/dsk/c0t0d0s6 1370511 96072 1219619 8% /export/home

      I really appreciate some help.

      Thanks a lot,

      Marcos

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    • Damien Carbery
      ... field that is ..%, but I d to take the only value without the % character. ... I know of two ways. 1) Use substitution to remove non-numeric chars. my
      Message 2 of 6 , Dec 14, 2006
        --- In perl-beginner@yahoogroups.com, Marcos Onisto <mlonisto@...> wrote:
        >
        > Hello,
        >
        > One more question. I have the output below, I'm taking the five
        field that is ..%, but I'd to take the only value without the % character.
        >
        > /dev/dsk/c0t0d0s0 491831 347447 95201 79% /
        > /dev/dsk/c0t0d0s3 17144018 3403114 13569464 21% /usr
        > /dev/dsk/c0t0d0s6 1370511 96072 1219619 8% /export/home
        >
        > Is there one easy way to do it?
        >
        > I really appreciate some help.
        >
        > Thanks a lot,
        >
        > Marcos
        >

        I know of two ways.

        1) Use substitution to remove non-numeric chars.
        my $Field5 = '14%';
        $Field5 =~ s/\D*//g;
        print "Field5 = $Field5\n"; # Prints 14

        2) Validate the data and use grouping to extract the numbers.
        my $Field5 = '14%';
        if ( $Field5 =~ /^(\d+)/ )
        {
        print "Match = $1\n"; # Prints 14
        }
        else
        {
        print "Bad data - do something!\n";
        }

        The advantage of the second method is that it confirms that the data
        is valid (i.e. begins with a digit). It allows you to take action when
        the data is invalid.

        >
        > Marcos Onisto <mlonisto@...> wrote:
        Hello,
        >
        > That's it! It's work but I'm trying to understand how It act.
        >
        > Thanks a lot,
        >
        > Marcos
        >
        > Robert Brown <rdabman4@...> wrote:
        One possible answer
        >
        > my ($strg,$pct)="";
        > my @flds=();
        > $strg="/dev/dsk/cotodos6 1370511 96072 1219619 8% /export/home";
        > @flds=split(" ",$strg);
        > $pct=$flds[4]; # arrays start from zero
        > print "Fifth column field is $pct\n";
        >
        > ----- Original Message ----
        > From: Marcos Onisto <mlonisto@...>
        > To: perl-beginner@yahoogroups.com
        > Sent: Monday, December 11, 2006 1:29:31 PM
        > Subject: [PBML] How can i take one column of one string?
        >
        > Hello All,
        >
        > I have one string that follow below. How can i take the 8% or
        exactly 5 column?
        >
        > /dev/dsk/c0t0d0s6 1370511 96072 1219619 8% /export/home
        >
        > I really appreciate some help.
        >
        > Thanks a lot,
        >
        > Marcos
      • Marcos Onisto
        Hello, I ll try it! Thanks a lot, Marcos ... field that is ..%, but I d to take the only value without the % character. ... I know of two ways. 1) Use
        Message 3 of 6 , Dec 14, 2006
          Hello,

          I'll try it!

          Thanks a lot,

          Marcos


          Damien Carbery <daymobrew@...> wrote: --- In perl-beginner@yahoogroups.com, Marcos Onisto <mlonisto@...> wrote:
          >
          > Hello,
          >
          > One more question. I have the output below, I'm taking the five
          field that is ..%, but I'd to take the only value without the % character.
          >
          > /dev/dsk/c0t0d0s0 491831 347447 95201 79% /
          > /dev/dsk/c0t0d0s3 17144018 3403114 13569464 21% /usr
          > /dev/dsk/c0t0d0s6 1370511 96072 1219619 8% /export/home
          >
          > Is there one easy way to do it?
          >
          > I really appreciate some help.
          >
          > Thanks a lot,
          >
          > Marcos
          >

          I know of two ways.

          1) Use substitution to remove non-numeric chars.
          my $Field5 = '14%';
          $Field5 =~ s/\D*//g;
          print "Field5 = $Field5\n"; # Prints 14

          2) Validate the data and use grouping to extract the numbers.
          my $Field5 = '14%';
          if ( $Field5 =~ /^(\d+)/ )
          {
          print "Match = $1\n"; # Prints 14
          }
          else
          {
          print "Bad data - do something!\n";
          }

          The advantage of the second method is that it confirms that the data
          is valid (i.e. begins with a digit). It allows you to take action when
          the data is invalid.

          >
          > Marcos Onisto <mlonisto@...> wrote:
          Hello,
          >
          > That's it! It's work but I'm trying to understand how It act.
          >
          > Thanks a lot,
          >
          > Marcos
          >
          > Robert Brown <rdabman4@...> wrote:
          One possible answer
          >
          > my ($strg,$pct)="";
          > my @flds=();
          > $strg="/dev/dsk/cotodos6 1370511 96072 1219619 8% /export/home";
          > @flds=split(" ",$strg);
          > $pct=$flds[4]; # arrays start from zero
          > print "Fifth column field is $pct\n";
          >
          > ----- Original Message ----
          > From: Marcos Onisto <mlonisto@...>
          > To: perl-beginner@yahoogroups.com
          > Sent: Monday, December 11, 2006 1:29:31 PM
          > Subject: [PBML] How can i take one column of one string?
          >
          > Hello All,
          >
          > I have one string that follow below. How can i take the 8% or
          exactly 5 column?
          >
          > /dev/dsk/c0t0d0s6 1370511 96072 1219619 8% /export/home
          >
          > I really appreciate some help.
          >
          > Thanks a lot,
          >
          > Marcos






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