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Re: [PBML] if syntax problem?

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  • Nathan.Jeffrey@dhs.vic.gov.au
    I think that... if ($monthflag = 1){$day2test = 2002%d%d , $nextmonth, $day2;} ...should read... $day2test = sprintf( 2002%d%d , $nextmonth, $day2) if
    Message 1 of 6 , Sep 4, 2002
    • 0 Attachment
      I think that...

      if ($monthflag = 1){$day2test = "2002%d%d", $nextmonth, $day2;}

      ...should read...

      $day2test = sprintf("2002%d%d", $nextmonth, $day2) if monthflag == 1;

      Two things - comparisons are '==' or 'eq' (for strings), not '='. And
      sprintf is the function to put C-style printf into strings :-)

      N






      "Evan Dembskey" <evan@...>
      04/09/2002 07:04 PM
      Please respond to perl-beginner


      To: "Perl-Beginner" <perl-beginner@yahoogroups.com>
      cc:
      Subject: [PBML] if syntax problem?


      Hi,


      What is wrong with my syntax here? I keep getting a "Useless use of a
      variable in void context at lotfix.pl line 57." error.



      $monthflag = 0;
      $nextmonth = 0;
      @months = (31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
      $temp2 = $months[$date];
      $temp3 = $temp2 + 1;
      if ($lastdate > $temp2){$monthflag = 1; $nextmonth = $date + 1;}

      #build day1
      $day1 = $firstdate;
      $day1test = "2002%d%d", $date, $day1;

      #build day2
      $temp = ($temp2 + $lastdate -4);
      if ($temp > $temp3){$temp = $temp - $temp3;}
      $day2 = $temp;
      if ($monthflag = 1){$day2test = "2002%d%d", $nextmonth, $day2;} #This
      is
      line 57
      else {$day2test = "2002%d%d", $date, $day2;}


      Regards,

      Jim



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