## Re: "ocaml_beginners"::[] What is the best way to code this data structure?

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• On Thu, Nov 1, 2012 at 3:04 AM, Gabriel Scherer ... Thank you for your help. I think this is probably the best way to go, but I m not sure how to figure out
Message 1 of 12 , Nov 1, 2012
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On Thu, Nov 1, 2012 at 3:04 AM, Gabriel Scherer
<gabriel.scherer@...>wrote:

> **
>
>
> I'm fine with your solution (sometimes it's a good choice to get
> weaker static guarantees for less conceptual complexity), but I would
> like to point out that the polymorphic variant solution suggested by
> Lukasz should work as well, and propose a simpler solution based on
> irregular recursion:
>
> Lukasz-inspired solution:
>
> type ('x, 'o) lu = [ `X of 'x * ('x, 'o) ld | `S ]
> and ('x, 'o) ld = [ `O of 'o * ('x, 'o) ld | `S ]
>
> let rec iter doX doO doXS doOS = function
> | `S -> ()
> | `X (x, `S) -> doXS x
> | `O (o, `S) -> doOS o
> | `X (x, rest) -> doX x; iter doX doO doXS doOS rest
> | `O (o, rest) -> doO o; iter doX doO doXS doOS rest
>
> let () = iter print_int print_string (Printf.printf "%d\n") print_endline
> (`X (1, `O ("o", `X (2, `O ("oo", `S)))))
>
> Irregular recursive datatype:
>
> type ('x, 'o) alterning =
> | Stop
> | One of 'x * ('o, 'x) alterning
>
> (* abbreviation just to have a shorter signature *)
> type 't u = 't -> unit
>
> let rec iter : 'x 'o. 'x u -> 'o u -> 'x u -> 'o u -> ('x, 'o) alterning u
> =
> fun do1 do2 do1S do2S ->
> function
> | Stop -> ()
> | One (x, Stop) -> do1S x
> | One (x, rest) -> do1 x; iter do2 do1 do2S do1S rest
>
Thank you for your help. I think this is probably the best way to go, but
I'm not sure how to figure out if the head of the list is 'x or 'o so that
I can pass the right do functions to iter.

Someone else had suggested something similar to this, but in order to be
able to start the recursion, it seemed like I had to have an extra type:

type mylist = X of (xdata,odata) alternating | O of (odata, xdata)
alternating

Is that right or is there a way to do away with this extra step?

[Non-text portions of this message have been removed]
• ... Thanks, nice example of polymorphic recursion! Thank you for your help. I think this is probably the best way to go, but ... first. The unfortunate thing
Message 2 of 12 , Nov 1, 2012
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On Thu, Nov 1, 2012 at 5:22 PM, Max Hayden Chiz <max.chiz@...> wrote:

> **
>
>
> On Thu, Nov 1, 2012 at 3:04 AM, Gabriel Scherer
> <gabriel.scherer@...>wrote:
> >
> > Irregular recursive datatype:
> >
> > type ('x, 'o) alterning =
> > | Stop
> > | One of 'x * ('o, 'x) alterning
> >
> > (* abbreviation just to have a shorter signature *)
> > type 't u = 't -> unit
> >
> > let rec iter : 'x 'o. 'x u -> 'o u -> 'x u -> 'o u -> ('x, 'o) alterning
> u
> > =
> > fun do1 do2 do1S do2S ->
> > function
> > | Stop -> ()
> > | One (x, Stop) -> do1S x
> > | One (x, rest) -> do1 x; iter do2 do1 do2S do1S rest
> >
>
Thanks, nice example of polymorphic recursion!

Thank you for your help. I think this is probably the best way to go, but
> I'm not sure how to figure out if the head of the list is 'x or 'o so that
> I can pass the right do functions to iter.
>
> The type system will keep reminding you which kind of elements comes
first. The unfortunate thing is you will not be able to neither "just not
care", nor "be prepared for both cases" -- the type system will require
that in a single function you only allow one type of elements to come first

> Someone else had suggested something similar to this, but in order to be
> able to start the recursion, it seemed like I had to have an extra type:
>
> type mylist = X of (xdata,odata) alternating | O of (odata, xdata)
> alternating
>
> Is that right or is there a way to do away with this extra step?
>

This extra step remembers which kind of elements comes first, so that some
parts of your code can be agnostic about it, and other can handle both
cases by a single function. I think it's "right" (i.e. to avoid this step
and not introducing other complications you would need to go back to
polymorphic variant solution).

[Non-text portions of this message have been removed]
• ... type x = int type o = string type s = string type xos_list = { o0o: o option; xos: (x*o) list; xfo: x option; s: s } let do_some f = function None - () |
Message 3 of 12 , Nov 1, 2012
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> I'm not sure how to figure out if the head of the list is 'x or 'o

type x = int
type o = string
type s = string

type xos_list = {
o0o: o option;
xos: (x*o) list;
xfo: x option;
s: s }

let do_some f = function None -> () | Some x -> f x

let rec iter do_x do_o { o0o; xos; xfo; _ } =
do_some do_o o0o; List.iter (fun (x,o) -> do_x x; do_o o) xos;
do_some do_x xfo

let () = iter print_int print_string
{ o0o=None; xos = [(1,"o");(2,"oo")]; xfo = Some 3; s="example" }
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