regex to take out lines ending in series of = signs plus a quote
- dpasseng wrote:
> I need to run a file removing all lines that end in =========="Don,
> This includes the quote.
This will do as comments suggest unless there are other characters in
the line that need to be delimited.
; removes line, leaves blank line
;^!Replace .+\=+"$\n >> "" RSA
; removes line and blank line
^!Replace .+\=+"$\n >> "" RSA
hrs > hsavage@...
- don, hrs,
Some remarks about this...
.+=========" would work as well, it is simpler, and since Notetab's
regex engine is greedy it picks up all lines ending with ten dashes
and a ".
I do not think the $-sign is needed here, especially since you
include \n in the search criteria...
I think the first example should omit the \n.
If you do search for a new line at the end of a line, it will not
find the lasat occurence (if that happens to be on the last line
> ; removes line, leaves blank line
> ;^!Replace .+\=+"$\n >> "" RSA
> ; removes line and blank line
> ^!Replace .+\=+"$\n >> "" RSA