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22283Re: Finding gaps in a sequence

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  • flo.gehrke
    Dec 1, 2011

      I also went through your clip again (messages #22230, #22245). I like that formula '^$Calc(^%V1%*676 + ^%V2%*26 + ^%V3%)$' which, actually, seems to be the heart of your solution.

      So I combined it with some ideas of my first concept and managed to speed up your clip significantly. Originally, your clip needed 78 seconds (on my notebook) to check a list of 10,000 codes. The following version is doing it in 9 seconds:

      ^!SetHintInfo Working...
      ; Assign code list to array %List%
      ^!SetListDelimiter ^%NL%
      ^!SetArray %List%=^$GetText$
      ^!Set %AZ%="abcdefghijklmnopqrstuvwxyz"
      ^!Set %i%=1

      ; Save current code to variable for later output in case of gap
      ^!Set %CurrCode%=^%List^%i%%
      ; Convert code to number(with Joy's formula)
      ^!Set %First%=^$Convert(^%List^%i%%)$
      ^!Inc %First%
      ^!Inc %i%
      ^!If ^%i% > ^%List0% Out
      ^!Set %Second%=^$Convert(^%List^%i%%)$
      ^!IfSame ^%First% ^%Second% CodeToInt Else False

      ^!Append %Gaps%=^%CurrCode%^P
      ^!Goto CodeToInt

      ^!IfEmpty ^%Gaps% Next Else Skip_2
      ^!Info No gaps!
      ^!Goto Skip_3
      ^!Toolbar New Document
      ^!InsertText Gap found after...^P^%Gaps%
      ^!Toolbar Second Window

      The sublip with custom function ^$Convert$ and your formula is...

      ^!Set %C1%=^$StrIndex(^&;1)$
      ^!Set %C2%=^$StrIndex(^&;2)$
      ^!Set %C3%=^$StrIndex(^&;3)$
      ^!Set %V1%=^$StrPos(^%C1%;^%AZ%;0)$
      ^!Set %V2%=^$StrPos(^%C2%;^%AZ%;0)$
      ^!Set %V3%=^$StrPos(^%C3%;^%AZ%;0)$
      ^!Result ^$Calc(^%V1%*676 + ^%V2%*26 + ^%V3%)$

      Thanks again for your proposal! Maybe you'll have a look at this revised version...


      --- In ntb-clips@yahoogroups.com, "joy8388608" <mycroftj@...> wrote:
      > --- In ntb-clips@yahoogroups.com, "Eb" <ebbtidalflats@> wrote:
      > >
      > > Hi Flo,
      > >
      > > You have are right in what the hex conversion was supposed to do.
      > > In the mean time I found my original char to hex clip, which only converted a single digit. I applied the single-digit approach to your problem. While I got it to work, it just raised another problem.
      > >
      > > The alphabet is like a base-26 number set (English aplhabet), after shifting a to zero. Straight conversion to numbers creates gaps, where it rolls to the next digit, i.e. aaz --> aba has a gap of 26!, the value of the next digit, and azz to baa has a gap much larger!
      > Sorry if I misunderstood you but I'll reply just in case in order to save you possible extra work and confusion...
      > You said aaz to aba has a gap but you correctly noted a=0...z=25.
      > Therefore, aaz=(0*26^2 + 0*26 + 25)=25 and aba=(0*26^2 + 1*26 + 0)=26 - No gap. Likewise, azz=675 and baa=676. Again, no gap.
      > Hope this helps, sorry if I misunderstood.
      > Joy
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