## Right equation?

Expand Messages
• I m trying to figure out how long it will take to do a stripping run. According to the equations in the Compleat Distiller, 1 kw will distill 30ml of water per
Message 1 of 4 , Mar 9, 2007
I'm trying to figure out how long it will take to do a stripping run.
According to the equations in the Compleat Distiller, 1 kw will
distill 30ml of water per minute, and 89ml or ethanol per minute. If
my wort is 15% ethanol, then i would assume that it would produce
38.85ml per minute. (89-30=59, 15% of 59 = 8.85) Assuming that my
calculations are correct.

Unless the equation is taking into account the alcohol content in the
vapor, and not in the wort. Which in this case would be, (89-30=59,
60% of 59 = 35.4). This would give me 65.4ml of distillate per minute,
assuming an output of 60% ethanol.

Am I totally messed up on these equations, or am I getting close?

-Tyler
• methinks you have the concept a-over-t. Your distillation rate is actually your collection rate. This has next to nothing to do with how fast stuff is boiling,
Message 2 of 4 , Mar 10, 2007
methinks you have the concept a-over-t.
to nothing to do with how fast stuff is boiling, and everything to do
with the proportion you allow to return to the column vs. what you let
drip into your collection bottle (assuming you are not using a pot
still).
Even if you are using a pot still, you will want to control the heat
input, rather than powering it up for maximum speed.
Cheers
Rob.

--- tyler_97355 <kd7enm@...> wrote:

> I'm trying to figure out how long it will take to do a stripping run.
> According to the equations in the Compleat Distiller, 1 kw will
> distill 30ml of water per minute, and 89ml or ethanol per minute. If
> my wort is 15% ethanol, then i would assume that it would produce
> 38.85ml per minute. (89-30=59, 15% of 59 = 8.85) Assuming that my
> calculations are correct.
>
> Unless the equation is taking into account the alcohol content in the
> vapor, and not in the wort. Which in this case would be, (89-30=59,
> 60% of 59 = 35.4). This would give me 65.4ml of distillate per
> minute,
> assuming an output of 60% ethanol.
>
> Am I totally messed up on these equations, or am I getting close?
>
> -Tyler
>
>
>
>

Cheers,
Rob.

____________________________________________________________________________________
TV dinner still cooling?
Check out "Tonight's Picks" on Yahoo! TV.
http://tv.yahoo.com/
• What i was trying to do is figure out how long it would take to do a STRIPPING run. By figuring out how much alcohol i have in the wort, and what the
Message 3 of 4 , Mar 10, 2007
What i was trying to do is figure out how long it would take to do a
STRIPPING run. By figuring out how much alcohol i have in the wort,
and what the distillate strength will be when it comes out, I only
have to figure out what the rate of collection will be to find out a
rough idea of how long it will take.

If i was doing a spirit run using a reflux still, at a reflux ratio of
9:1, all i would have to do is take the estimated distillation rate,
and reduce it by 90% to find out how long it would take to do a spirit
run.

--- In new_distillers@yahoogroups.com, Robert Thomas <whosbrewing@...>
wrote:
>
> methinks you have the concept a-over-t.
> Your distillation rate is actually your collection rate. This has next
> to nothing to do with how fast stuff is boiling, and everything to do
> with the proportion you allow to return to the column vs. what you let
> drip into your collection bottle (assuming you are not using a pot
> still).
> Even if you are using a pot still, you will want to control the heat
> input, rather than powering it up for maximum speed.
> Cheers
> Rob.
>
>
> --- tyler_97355 <kd7enm@...> wrote:
>
> > I'm trying to figure out how long it will take to do a stripping run.
> > According to the equations in the Compleat Distiller, 1 kw will
> > distill 30ml of water per minute, and 89ml or ethanol per minute. If
> > my wort is 15% ethanol, then i would assume that it would produce
> > 38.85ml per minute. (89-30=59, 15% of 59 = 8.85) Assuming that my
> > calculations are correct.
> >
> > Unless the equation is taking into account the alcohol content in the
> > vapor, and not in the wort. Which in this case would be, (89-30=59,
> > 60% of 59 = 35.4). This would give me 65.4ml of distillate per
> > minute,
> > assuming an output of 60% ethanol.
> >
> > Am I totally messed up on these equations, or am I getting close?
> >
> > -Tyler
> >
> >
> >
> >
>
>
> Cheers,
> Rob.
>
>
>
>
____________________________________________________________________________________
> TV dinner still cooling?
> Check out "Tonight's Picks" on Yahoo! TV.
> http://tv.yahoo.com/
>
• ... stripping run. ... minute. If ... produce ... my ... in the ... 30=59, ... close? ... If you have a continuous feed column you can work out product vs
Message 4 of 4 , Mar 10, 2007
--- In new_distillers@yahoogroups.com, "tyler_97355" <kd7enm@...>
wrote:
> >
> > > I'm trying to figure out how long it will take to do a
stripping run.
> > > According to the equations in the Compleat Distiller, 1 kw will
> > > distill 30ml of water per minute, and 89ml or ethanol per
minute. If
> > > my wort is 15% ethanol, then i would assume that it would
produce
> > > 38.85ml per minute. (89-30=59, 15% of 59 = 8.85) Assuming that
my
> > > calculations are correct.
> > >
> > > Unless the equation is taking into account the alcohol content
in the
> > > vapor, and not in the wort. Which in this case would be, (89-
30=59,
> > > 60% of 59 = 35.4). This would give me 65.4ml of distillate per
> > > minute,
> > > assuming an output of 60% ethanol.
> > >
> > > Am I totally messed up on these equations, or am I getting
close?
> > >
> > > -Tyler

If you have a continuous feed column you can work out product vs
time. Known rate of beer feed per hour at a constant alc. strength
and a constant heat input will give that one. Many Commercial
whiskey makers use this method to strip, then put the strip results
into a potstill for final production.

But a potstill or reflux still is different, because the percentage
of alc. strength in the charge (the feed) keeps changing. When do
you decide that diminishing returns isn't worth it? At 5%? Or 2%?
The more alc. you remove, the longer it takes to remove the next
given amount.

It's not linear. Therefore, time-trials with your particular setup,
and your particular strength of wash, is the only reliable guide.

Slainte!
regards Harry
Your message has been successfully submitted and would be delivered to recipients shortly.