## Re: help - heating element

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• ... 1 / 2.25 / ... diameters, ... =============================== thanks Mike, that clears it up I ll take it as Vapor Speed 101 much appreciated BR
Message 1 of 10 , Oct 27, 2004
--- In new_distillers@yahoogroups.com, "Mike Nixon" <mike@s...> wrote:
>
> So cross-sectional areas are in this proportion: 2" / 3" / 4" =
1 / 2.25 /
> 4
>
> So, if 750W gives 11"/sec @ 2"
> then
> 750W gives 11/2.25 = 4.9"/sec @ 3"
> 1125W gives 4.9 x 1125/750 = 7.35"/sec @ 3"
> 1875W gives 4.9 x 1875/750 = 12.25"/sec @ 3"
> and
> 750W gives 11/4 = 2.75"/sec @ 4"
> 1500W gives 2.75 x 1500/750 = 5.5"/sec @ 4"
> 3000W gives 2.75 x 3000/750 = 11"/sec @ 4"
>
> Soooooooo.........
> if you want mid and max figures of wattage for each of those
diameters,
> taking 10"/sec as mid and 20"/sec as max
> 1534W 10"/sec @ 3"
> 3068W 20"/sec @ 3"
> 2727W 10"/sec @ 4"
> 5455W 20"/sec @ 4"
>
> Please see me after class :-))
>
> All the best,
> Mike N
===============================
thanks Mike, that clears it up
I'll take it as Vapor Speed 101

much appreciated
BR
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