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Re: help - heating element

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  • bradr36
    ... 1 / 2.25 / ... diameters, ... =============================== thanks Mike, that clears it up I ll take it as Vapor Speed 101 much appreciated BR
    Message 1 of 10 , Oct 27, 2004
      --- In new_distillers@yahoogroups.com, "Mike Nixon" <mike@s...> wrote:
      >
      > So cross-sectional areas are in this proportion: 2" / 3" / 4" =
      1 / 2.25 /
      > 4
      >
      > So, if 750W gives 11"/sec @ 2"
      > then
      > 750W gives 11/2.25 = 4.9"/sec @ 3"
      > 1125W gives 4.9 x 1125/750 = 7.35"/sec @ 3"
      > 1875W gives 4.9 x 1875/750 = 12.25"/sec @ 3"
      > and
      > 750W gives 11/4 = 2.75"/sec @ 4"
      > 1500W gives 2.75 x 1500/750 = 5.5"/sec @ 4"
      > 3000W gives 2.75 x 3000/750 = 11"/sec @ 4"
      >
      > Soooooooo.........
      > if you want mid and max figures of wattage for each of those
      diameters,
      > taking 10"/sec as mid and 20"/sec as max
      > 1534W 10"/sec @ 3"
      > 3068W 20"/sec @ 3"
      > 2727W 10"/sec @ 4"
      > 5455W 20"/sec @ 4"
      >
      > Please see me after class :-))
      >
      > All the best,
      > Mike N
      ===============================
      thanks Mike, that clears it up
      I'll take it as Vapor Speed 101

      much appreciated
      BR
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