## 2043Re: [ai-geostats] A quasi-stationary framework...

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• May 7 12:13 AM
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The variogram is only the difference between the absolute values of the
subtract the mean from every z(x), you will still have the same variogram?

----- Original Message -----
From: "Simone Sammartino" <marenostrum@...>
To: "Geostat newsgroup" <ai-geostats@...>
Sent: Wednesday, May 04, 2005 11:36 PM
Subject: [ai-geostats] A quasi-stationary framework...

It's me again!...:-))
My problem now is:
Assume Z(x) is not exactly stationary but its mean varies weakly in the
space...
Thus E[Z(x)]=m(x)...let's consider a new variable, said residual,
Y(x)=Z(x)-m(x), with zero mean.
Variogram for Z(x) is
(1) 2*Gamma(x)=E{[Z(x)-Z(x+h)]^2}-[m(x)-m(x+h)]^2
At this point the book says "...and it's easy to realize how variogram of
Y(x) is exactly the same of (1)..." How??!?!?!?
I tried everything but I did not manage to obtain the same result....
Anyone helping me?
Thanks as always
Simone

-----------------------------
Dr. Simone Sammartino
PhD student
- Geostatistical analyst
- G.I.S. mapping
I.A.M.C. - C.N.R.
Geomare-Sud section
Port of Naples - Naples
marenostrum@...
-----------------------------

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