The variogram is only the difference between the absolute values of the

grade, so if you

subtract the mean from every z(x), you will still have the same variogram?

----- Original Message -----

From: "Simone Sammartino" <marenostrum@...>

To: "Geostat newsgroup" <ai-geostats@...>

Sent: Wednesday, May 04, 2005 11:36 PM

Subject: [ai-geostats] A quasi-stationary framework...

It's me again!...:-))

My problem now is:

about a quasi-stationary framework...

Assume Z(x) is not exactly stationary but its mean varies weakly in the

space...

Thus E[Z(x)]=m(x)...let's consider a new variable, said residual,

Y(x)=Z(x)-m(x), with zero mean.

Variogram for Z(x) is

(1) 2*Gamma(x)=E{[Z(x)-Z(x+h)]^2}-[m(x)-m(x+h)]^2

At this point the book says "...and it's easy to realize how variogram of

Y(x) is exactly the same of (1)..." How??!?!?!?

I tried everything but I did not manage to obtain the same result....

Anyone helping me?

Thanks as always

Simone

-----------------------------

Dr. Simone Sammartino

PhD student

- Geostatistical analyst

- G.I.S. mapping

I.A.M.C. - C.N.R.

Geomare-Sud section

Port of Naples - Naples

marenostrum@...

-----------------------------

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