## 2040Re: [ai-geostats] A quasi-stationary framework...

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• May 10, 2005
Thank you for reply but I wanted to understand it in a pure formal mathematical framework...
Simone

> The variogram is only the difference between the absolute values of the
> subtract the mean from every z(x), you will still have the same variogram?
>
> ----- Original Message -----
> From: "Simone Sammartino" <marenostrum@...>
> To: "Geostat newsgroup" <ai-geostats@...>
> Sent: Wednesday, May 04, 2005 11:36 PM
> Subject: [ai-geostats] A quasi-stationary framework...
>
>
> It's me again!...:-))
> My problem now is:
> Assume Z(x) is not exactly stationary but its mean varies weakly in the
> space...
> Thus E[Z(x)]=m(x)...let's consider a new variable, said residual,
> Y(x)=Z(x)-m(x), with zero mean.
> Variogram for Z(x) is
> (1) 2*Gamma(x)=E{[Z(x)-Z(x+h)]^2}-[m(x)-m(x+h)]^2
> At this point the book says "...and it's easy to realize how variogram of
> Y(x) is exactly the same of (1)..." How??!?!?!?
> I tried everything but I did not manage to obtain the same result....
> Anyone helping me?
> Thanks as always
> Simone
>
>
> -----------------------------
> Dr. Simone Sammartino
> PhD student
> - Geostatistical analyst
> - G.I.S. mapping
> I.A.M.C. - C.N.R.
> Geomare-Sud section
> Port of Naples - Naples
> marenostrum@...
> -----------------------------
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-----------------------------
Dr. Simone Sammartino
PhD student
- Geostatistical analyst
- G.I.S. mapping
I.A.M.C. - C.N.R.
Geomare-Sud section
Port of Naples - Naples
marenostrum@...
-----------------------------

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6X velocizzare la tua navigazione a 56k? 6X Web Accelerator di Libero!
Scaricalo su INTERNET GRATIS 6X http://www.libero.it
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